Hello!

du/dt=5*d^2u/dx^2

Initial condition: u(x,0)=f(x)=3*sin(2*x)+6*sin(5*x)

Boundery condition: u(0,t)=u(Pi,t)=0

t>=0, x=[0,Pi], du is partial derivate

How to do thi in Maple?

Kjell

Printable View

- July 21st 2012, 07:35 AMkjellPartial Differential Equation- Maple
Hello!

du/dt=5*d^2u/dx^2

Initial condition: u(x,0)=f(x)=3*sin(2*x)+6*sin(5*x)

Boundery condition: u(0,t)=u(Pi,t)=0

t>=0, x=[0,Pi], du is partial derivate

How to do thi in Maple?

Kjell - July 21st 2012, 09:01 AMProve ItRe: Partial Differential Equation- Maple
- July 21st 2012, 09:39 AMkjellRe: Partial Differential Equation- Maple
yes, but I would like to learn how to solve it in Maple

Kjell