Hi all.
I started with this equation:
$\displaystyle \frac {dy}{dx}=tan^2(x+y)$
I made the substitution $\displaystyle u = x+y$ and am now looking at this:
$\displaystyle \frac {du}{tan^2u+1} = dx$
How the heck do I integrate that left side?
Hi all.
I started with this equation:
$\displaystyle \frac {dy}{dx}=tan^2(x+y)$
I made the substitution $\displaystyle u = x+y$ and am now looking at this:
$\displaystyle \frac {du}{tan^2u+1} = dx$
How the heck do I integrate that left side?