I have the original equation as $\displaystyle y'' +1.4y^2y' - 1.4y'+2y = 0; y(0) = 0, y'(0) = -1$
I read that to solve this I need to break this into two 1st order differential equations, which i do through subsitution, getting:
$\displaystyle x_1' = x_2; x_1(0) = 0$ and
$\displaystyle x_2' = -1.4x_1x_2 - 1.4x_2 + 2x_1; x_2(0) = -1$
but how does this help me? I still cant seem to solve the DEs
I'm pretty sure i need to solve$\displaystyle x_2'$ to get $\displaystyle x_1$ then i can get the exact solution to y. but i'm at a loss of what to do now.