Look at this link under "Second Order Differential equations", the first example will show you how to proceed.
First and Second Order Differential Equations
I'm working on a problem that asks me to find a formula that'll give all possible solutions to the equation V'' + (2/3)V'(r) = 0. I'm not certain where to begin. I believe that solving for V'(r) would be a nice first step, but I don't know how to go about this either. ANy guidance would be greatly appreciated. Thank you!
Thank you for the link pickslides.
From what I've gotten, the solution should be something akin to y = c(sub 1)e^(r(sub1)x) + c(sub 2)e^(r(sub 2)x). The solution to r^2 - (2/r)r = 0 is plus or minus square root of 2. The solution, then, appears to be y = c(sub 1)e^(sqrt(2)x) + c(sub 2)e^(-sqrt(2)x). Is this correct? Thank you once again for your assistance.
pickslides, I'm so sorry. I typed the coefficient (2/3) in the original problem when the problem states (2/r). I typed my attempt at a solution with regard to that. I apologize sincerely for my mistake. You've been very kind with your explanation, and I thank you.
This makes things more difficult.
Have a look at this link
solve y''+(2/x)y' =0 - Wolfram|Alpha