Let , where is a function with as argument ,then :
Hence :
hey,
I have this question I have been trying to solve, I got some help and I think I may have solved it but I just wanted to double check here ,
The question is, Consider the non-linear equation below, use y'=p to reduce it to first order, y(o)=1 and y'(0)=-1
y''+y(y')^{3}=0
so
Then
1=1-2c
c=0
Does this look correct?
Thanks in advance
So using your method the solution would be
Is that right?
Edit:
Hold on that's not right, just working it out quickly now
I get
y^{3 }- 3/2 y = 6x - 1/2
Does that look right?