Thread: y' + y = 3y^2

what s the solution of y' + y = 3y^2 which graphic contans the pont(1,1).

thank you for ur help

Originally Posted by ienavolante

what s the solution of y' + y = 3y^2 which graphic contans the pont(1,1).

thank you for ur help

$\displaystyle \frac{dy}{dx}=3y^2-y$

$\displaystyle \int\frac{dy}{3y^2-y}=\int dx$

Can you proceed?

i still have problems with that integral..

Looks like partial fractions will be needed.

Originally Posted by ienavolante

i still have problems with that integral..

What have you tried? Where are you stuck? Have you consulted your class notes or textbook? If you are trying to solve differential equations, it is expected that you have the necessary experience in techniques of integration or have gone back and thoroughly revised those techniques ....