Dear all

Hi,

I seek the solution of the 4th order ordinary differential equation as follows:

d^4(y) / dx^4 + G * y = H

for the homogenous relation which is:

d^4(y) / dx^4 + G * y = 0

or

G=4*b^4

d^4(y) / dx^4 + 4*b^4 * y = 0

we assume the solution of the bellow form:

y=exp(b*x)*(A*cos(b*x)+B*sin(b*x))+exp(-b*x)*(C*cos(b*x)+D*sin(b*x))

Now what is the private solution for the inhomogenous equation?