Dear all
Hi,
I seek the solution of the 4th order ordinary differential equation as follows:
d^4(y) / dx^4 + G * y = H
for the homogenous relation which is:
d^4(y) / dx^4 + G * y = 0
or
G=4*b^4
d^4(y) / dx^4 + 4*b^4 * y = 0
we assume the solution of the bellow form:
y=exp(b*x)*(A*cos(b*x)+B*sin(b*x))+exp(-b*x)*(C*cos(b*x)+D*sin(b*x))
Now what is the private solution for the inhomogenous equation?