Apologies. Darn Latex. Cannot get it to work for the life of me!
L[y] = \frac{2(s+5)}{(s+5)^2+1/2} + {10}{(s+5)^2+1/2}
Solution to that gives
y = 2e^-5t cos(\frac{t}{\sqrt{2}}) + 10\sqrt{2}e^-5t sin(\frac{t}{\sqrt{2}}).
Apologies. Darn Latex. Cannot get it to work for the life of me!
L[y] = \frac{2(s+5)}{(s+5)^2+1/2} + {10}{(s+5)^2+1/2}
Solution to that gives
y = 2e^-5t cos(\frac{t}{\sqrt{2}}) + 10\sqrt{2}e^-5t sin(\frac{t}{\sqrt{2}}).