As you know Mercury orbits with precession: http://physics.ucr.edu/~wudka/Physics7/Notes_www/node98.html
Could you help to calculate precession of the Mercury in this new way?
Lets use Newton's law for gravitational attraction.
But lets assume that inertial mass m is changing due motion and due gravitation by equation
m = m0 / sqrt( 1-(z/c)^2 )
m0 – rest mass of the Mercury ( which is used to calculate gravitational force and kinetic mass )
m – kinetic mass of Mercury ( which is used to calculate momentum )
For z lets consider two possible versions:
z = | v + v_escape |
and version 2
z = 2*| v + v_escape |*| v - v_escape | / ( | v + v_escape | + | v – v_escape | )
where v and v_escape are vectors
v - real velocity of the Mercury
v_escape - escape from the Sun velocity (at the location of the Mercury)
v_escape vector points straight away from the Sun.
Now you can use Newton gravitation law with rest mass m0
and kinetic mass m could be used to calculate momentum of the Mercury.
Could you help to calculate precession by using mentioned assumptions?