As you know Mercury orbits with precession: http://physics.ucr.edu/~wudka/Physics7/Notes_www/node98.html

Could you help to calculate precession of the Mercury in this new way?

See picture:

http://www.part.lt/img/f628e573d6f02...10de240722.png

Lets use Newton's law for gravitational attraction.

But lets assume that inertial mass m is changing due motion and due gravitation by equation

m = m0 / sqrt( 1-(z/c)^2 )

where

m0 – rest mass of the Mercury ( which is used to calculate gravitational force and kinetic mass )

m – kinetic mass of Mercury ( which is used to calculate momentum )

For z lets consider two possible versions:

version 1

z = |v+v_escape|

and version 2

z = 2*|v+v_escape|*|v-v_escape| / ( |v+v_escape| + |v–v_escape| )

wherevandv_escapeare vectors

v- real velocity of the Mercury

v_escape- escape from the Sun velocity (at the location of the Mercury)

v_escapevector points straight away from the Sun.

Now you can use Newton gravitation law with rest mass m0

and kinetic mass m could be used to calculate momentum of the Mercury.

Could you help to calculate precession by using mentioned assumptions?

Thank you.