Find the Laplace transformation of the piecewise function.
f(t) = t+1, 0≤t≤1
f(t) = t^2, t>1
Sketch the graph of f(t)
i use the g(t)[u(t-a)-u(t-b)] and i get:
(t+1)[u(t-0)-u(t-1)]+(t^2)u(t-1)
and that gives:
(t+1)-(t+1)u(t-1)+(t^2)u(t-1)
and then i can take the Laplace
L[t]+L[1]+L[(t+1)u(t-1)]+L[(t^2)u(t-1)]
after much calculation i got answer which was wrong
I'm pretty sure i messed up trying to take the laplace of "L[(t+1)u(t-1)]+L[(t^2)u(t-1)]"
Any help?


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