Differentiating both sides of we get or equivalently (this is the solution)
Differentiating w.r.t.x we have
2x-2+2y dy/dx-2dy/dx =0 So,x - 1+ydy/dx-dy/dx =0
differentiating again w.r.t.x,we get
Now how to calculate required differential equation.
If my calculations of 1st and 2nd order derivative is wrong, reply me accordingly.
You are correct. Original problem is as follows:
Find the differential equation of all circles having a fixed radius a.
Answer given in the study material is as below:
Hence give me a hint to arrive at the above answer.
I found the differential equation of all circles having fixed radius a.First derivative of equation of these circles is
Second derivative of equation of these circles is
Differential equation of all circles having fixed radius a is given in post number #5 to this thread.
However thanks for your reply.