Dear all,
I already calculate the differential below.. and i want to check it whether the answer that I got is correct or not.
X= [ x xdot psi psidot y ydot z zdot]
solve d/dX (m1/m2*psidot/cos^2 psi )
= [0 0 (2*m1/m2*sec^2 psi *tan psi* psidot) (m1/m2*sec^2 psi) 0 0 0 0]
= (m1/m2)*sec^2 psi [ 0 0 (2 *tan psi* psidot) 1 0 0 0 0]
Thank you very much.
You appear to be attempting to solve a vector differential equation. However, the ambiguities in your notation are too great to decipher. I would recommend using LaTeX to write your DE. For example, the codeOriginally Posted by ain
[TEX]\frac{d}{dt}\left[\begin{array}{c}x\\y\\z\end{array}\right]=\left[\begin{array}{c}\dot{x}\\ \dot{y}\\ \dot{z}\end{array}\right].[/TEX]
produces the output
![\frac{d}{dt}\left[\begin{array}{c}x\\y\\z\end{array}\right]=\left[\begin{array}{c}\dot{x}\\ \dot{y}\\ \dot{z}\end{array}\right].](http://latex.codecogs.com/png.latex?\frac{d}{dt}\left[\begin{array}{c}x\\y\\z\end{array}\right]=\left[\begin{array}{c}\dot{x}\\ \dot{y}\\ \dot{z}\end{array}\right].)
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