where u_x is u(x,y) differentiated with respect to x and u_xy is u(x,y) twice differentiated with respect to x and with respect to y
How would I go about solving this?
Thanks for any help.
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where u_x is u(x,y) differentiated with respect to x and u_xy is u(x,y) twice differentiated with respect to x and with respect to y
How would I go about solving this?
Thanks for any help.
I'm pretty sure I've done it now actually.
u = e^(ax+2y)
What you present is just one solution. Here are two more
(1)
(2)
Why not letand see where that gets you.
This gives 2v + v_y = 0Quote:
Originally Posted by Danny
Why not let
I'm not really sure what to do
Separate and integrate noting that you'll get a function of integration.
Since only differentiation with respect to y is involved, you can solve that as the ODE
. Of course, the "constant" may be a function of x. What does that give you for v? What does that make the orginal equation?
Remember that the general solution to a partial differential equation may involve unknown functions of the variables rather than unknown constants.
surely you mean dv/dy = -2v ?Quote:
Originally Posted by HallsofIvySince only differentiation with respect to y is involved, you can solve that as the ODE
I'm sure that's what HoI meant.Quote:
Originally Posted by feyomi