# Non-exact differential equation help

• Oct 9th 2011, 02:29 PM
evant8950
Non-exact differential equation help
Hey everyone,

I have this problem $y(x-y-2)dx + x(y-x+4)dy = 0$

I get an integration factor of $y^3$ but when I multiply both equations by this they are not exact, what am I doing wrong?

Thanks
• Oct 9th 2011, 03:35 PM
Jester
Re: Non-exact differential equation help
Check your sign. I believe it should be $\frac{1}{y^3}$.
• Oct 9th 2011, 03:39 PM
evant8950
Re: Non-exact differential equation help
I got it. It was my sign. I appreciate your help.