How do I solve this one?
(2x - y + 4)dy + (x - 2y + 5)dx = 0
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Originally Posted by mafra How do I solve this one?
(2x - y + 4)dy + (x - 2y + 5)dx = 0 Find the point of intersection of the two lines 2x - y + 4 = 0, and x - 2y + 5 = 0. Suppose that intersection occurs at the point Then do the substitution and
The result of this substitution should result in a recognizeable type of DE. What do you get?
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