I am having trouble solving the following differential equation:
4xy + 6y^2 + (2x^2 + 6xy)y' = 0
I have tried to bring it into the form y' + p(x)y = r(x) but cannot, thereby thinking it is a Bernoulli Equation. When I try to put it into Bernoulli form and get the y' by itself, I am left with the (2x^2 + 6xy) in the denominator of the other terms, making it impossible to solve.