Differential Equation y'=sin(y-t) y(0)=0

I got y=2arctan(t/(t-2))+t but the program I'm using for school says I'm wrong. I looked it up on wolfram and it gave me something completely different but that was wrong too. I did the work myself twice and got y=2arctan(t/(t-2))+t. What do you guys get? Thanks.

Re: Differential Equation y'=sin(y-t) y(0)=0

Re: Differential Equation y'=sin(y-t) y(0)=0

Re: Differential Equation y'=sin(y-t) y(0)=0

And so that becomes y=2arctan(t/(t+1))+t

well thanks for the help guys. I ended up getting the question wrong, but I think it's a problem with the program.

Re: Differential Equation y'=sin(y-t) y(0)=0

But what was wrong with my post (#2)?

Edit: Never mind, figured it out.

Re: Differential Equation y'=sin(y-t) y(0)=0

Quote:

Originally Posted by

**beanus** And so that becomes y=2arctan(t/(t+1))+t

well thanks for the help guys. I ended up getting the question wrong, but I think it's a problem with the program.

See the edits to my post...