dy/dx= x / (x^2y+y^3)

its been a while since I had diff eq and this problem came up, could i get some help please?

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- Aug 28th 2011, 08:56 PM #1

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- Aug 28th 2011, 09:00 PM #2

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- Aug 29th 2011, 12:37 AM #4
## Re: dy/dx= x / (x^2y+y^3)

Writing the DE in different way, changing the role of x and y, You obtain...

$\displaystyle \frac{d x}{dy} = x\ y + \frac{y^{3}}{x}$ (1)

... which is 'Bernoulli type'. The solving procedure is illustrated in...

Bernoulli Differential Equation -- from Wolfram MathWorld

It is remarkable the fact that a Bernoulli equation has standard form...

$\displaystyle x^{'} + p(y)\ x = q(y)\ x^{n}$ (2)

... and the solving procedure is valid also when n is a negative number like in this case [n=-1...]

Kind regards

$\displaystyle \chi$ $\displaystyle \sigma$

- Aug 29th 2011, 12:48 AM #5

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