Find the equation of the curve which passes through the origin and the tangent to which at every point (x,y) has a slope equal to: {x^4+2xy-1}/{1+x^2} Hence dy/dx={x^4+2xy-1}/{1+x^2} How do i separate the 'xy' term?
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This is now first-order linear, so use the integrating factor method.
Originally Posted by animesh271094 Hence dy/dx={x^4+2xy-1}/{1+x^2} How do i separate the 'xy' term? The equation has an integrating factor $\displaystyle \mu=\mu (x)$ that depends on $\displaystyle x$ . Edited: Sorry, I didn't see Prove It's post.
Last edited by FernandoRevilla; Aug 15th 2011 at 02:55 AM.
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