# Math Help - Slope = [(x^4+2xy-1)/(1+x^2)]

1. ## Slope = [(x^4+2xy-1)/(1+x^2)]

Find the equation of the curve which passes through the origin and the tangent to which at every point (x,y) has a slope equal to:

{x^4+2xy-1}/{1+x^2}

Hence dy/dx={x^4+2xy-1}/{1+x^2}
How do i separate the 'xy' term?

2. ## Re: Slope = [(x^4+2xy-1)/(1+x^2)]

This is now first-order linear, so use the integrating factor method.

3. ## Re: Slope = [(x^4+2xy-1)/(1+x^2)]

Originally Posted by animesh271094
Hence dy/dx={x^4+2xy-1}/{1+x^2}
How do i separate the 'xy' term?
The equation has an integrating factor $\mu=\mu (x)$ that depends on $x$ .

Edited: Sorry, I didn't see Prove It's post.