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Math Help - Slope = [(x^4+2xy-1)/(1+x^2)]

  1. #1
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    Slope = [(x^4+2xy-1)/(1+x^2)]

    Find the equation of the curve which passes through the origin and the tangent to which at every point (x,y) has a slope equal to:

    {x^4+2xy-1}/{1+x^2}

    Hence dy/dx={x^4+2xy-1}/{1+x^2}
    How do i separate the 'xy' term?
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  2. #2
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    Re: Slope = [(x^4+2xy-1)/(1+x^2)]



    This is now first-order linear, so use the integrating factor method.
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  3. #3
    MHF Contributor FernandoRevilla's Avatar
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    Re: Slope = [(x^4+2xy-1)/(1+x^2)]

    Quote Originally Posted by animesh271094 View Post
    Hence dy/dx={x^4+2xy-1}/{1+x^2}
    How do i separate the 'xy' term?
    The equation has an integrating factor \mu=\mu (x) that depends on x .


    Edited: Sorry, I didn't see Prove It's post.
    Last edited by FernandoRevilla; August 15th 2011 at 03:55 AM.
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