I have the question

2) Find the general solution of the following differential equation:

>> dy/dx = y^2 -1/x

i have fount the general solution to be:

re arrange>> 1/y^2 -1 dy = -1/x dx

integrate>> 1/2 ln(y-1) - 1/2 ln(y+1) = lnx + C

is that correct?? Or can i simplify further??