I have the question
2) Find the general solution of the following differential equation:
>> dy/dx = y^2 -1/x
i have fount the general solution to be:
re arrange>> 1/y^2 -1 dy = -1/x dx
integrate>> 1/2 ln(y-1) - 1/2 ln(y+1) = lnx + C
is that correct?? Or can i simplify further??