$\displaystyle xy'=\sqrt{x^2-y^2}+y$ So far I've rearranged it to get: $\displaystyle \frac{dy}{dx}=\frac{\sqrt{x^2-y^2}+y}{x}$ Thanks
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Now the RHS is rewritten as $\displaystyle \sqrt{1-{{\left( \frac{y}{x} \right)}^{2}}}+\frac{y}{x}.$