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Math Help - Solving dy/dx = cot(x+y)-1.

  1. #1
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    Solving dy/dx = cot(x+y)-1.

    hello guys, have tried but to no avail on this problem:

    dy/dx = cot(x+y)-1

    pls help out! thanks.
    Last edited by mr fantastic; July 27th 2011 at 04:31 PM. Reason: Re-titled.
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  2. #2
    A Plied Mathematician
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    Re: varible seperable differencial equation. pls help!

    Try a substitution: u = y + x. I think your DE will simplify considerably.
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  3. #3
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    detail on problem am having on variable saparable diff. equation!

    let me make it clearer guys;

    the equation is dy/dx = cot(y+x)-1

    solution is Cos(y+x)=ce-x


    my problem is the process leading to the solution and was solved using variable saperable differencial equation


    thanks for ur assistance.
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  4. #4
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    Re: detail on problem am having on variable saparable diff. equation!

    Quote Originally Posted by lawochekel View Post
    let me make it clearer guys;

    the equation is dy/dx = cot(y+x)-1

    solution is Cos(y+x)=ce-x


    my problem is the process leading to the solution and was solved using variable saperable differencial equation


    thanks for ur assistance.
    Substitute y+x=u

    \frac{dy}{dx}+1=\frac{du}{dx}
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  5. #5
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    Re: detail on problem am having on variable saparable diff. equation!

    Quote Originally Posted by lawochekel View Post
    let me make it clearer guys;

    the equation is dy/dx = cot(y+x)-1

    solution is Cos(y+x)=ce-x


    my problem is the process leading to the solution and was solved using variable saperable differencial equation


    thanks for ur assistance.
    You were told what to do in post #2. Did you try following that suggestion? What have you tried? Where are you still stuck?
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