hi all, i have the following question puzzling me: (dy/dx) = 10^(x+y) how do i solve it?
Follow Math Help Forum on Facebook and Google+
Originally Posted by vonflex1 hi all, i have the following question puzzling me: (dy/dx) = 10^(x+y) how do i solve it? Notice that $\displaystyle \int 10^{-y}dy=\int 10^xdx$.
Hello, Maybe, you can use, that $\displaystyle 10^{-y} = e^{-y \ln 10}~.$ Then you get the simple ODE: $\displaystyle \frac{d}{dx} \left( -\frac{1}{\ln 10} 10^{-y} \right) = 10^x~.$
Of course, the first step, which then leads to what hatsoff and Chandler26 said, is to recognize that $\displaystyle 10^{x+y}= 10^x10^y$.
View Tag Cloud