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Math Help - Solve y'=1/[2x+(e^(4y)]

  1. #1
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    Solve y'=1/[2x+(e^(4y)]

    I need help to solve this equation, anyone could help me out?
    y'=1/[2x+(e^(4y)] solve for y.
    Last edited by mr fantastic; July 7th 2011 at 02:21 PM. Reason: Title.
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  2. #2
    MHF Contributor chisigma's Avatar
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    Re: Solve y'=1/[2x+(e^(4y)]

    Quote Originally Posted by ryan1573 View Post
    I need help to solve this equation, anyone could help me out?
    y'=1/[2x+(e^(4y)] solve for y.
    Why don't write the DE as...

    \frac{d x}{d y} = 2 x + e^{4 y} (1)

    ... so that we have a linear DE?...

    Kind regards

    \chi \sigma
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  3. #3
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    Re: Solve y'=1/[2x+(e^(4y)]

    No , the equation is 1 divided by the whole things, dy/dx =1/[2x+(e^(4y)]
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  4. #4
    MHF Contributor Also sprach Zarathustra's Avatar
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    Re: Solve y'=1/[2x+(e^(4y)]

    Quote Originally Posted by ryan1573 View Post
    No , the equation is 1 divided by the whole things, dy/dx =1/[2x+(e^(4y)]

    dy =dx/[2x+(e^(4y)]

    [2x+(e^(4y)]dy=dx

    [2x+(e^(4y)]=dx/dy
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  5. #5
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    Re: Solve y'=1/[2x+(e^(4y)]

    Quote Originally Posted by ryan1573 View Post
    No , the equation is 1 divided by the whole things, dy/dx =1/[2x+(e^(4y)]
    Yes, it is. And that is equivalent to dx/dy= 2x+ e^(4y), as chisigma suggested!

    You have now had three people suggest the same way to solv this problem- try it!
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