I need help to solve this equation, anyone could help me out? y'=1/[2x+(e^(4y)] solve for y.
Last edited by mr fantastic; Jul 7th 2011 at 02:21 PM. Reason: Title.
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Originally Posted by ryan1573 I need help to solve this equation, anyone could help me out? y'=1/[2x+(e^(4y)] solve for y. Why don't write the DE as... $\displaystyle \frac{d x}{d y} = 2 x + e^{4 y} $ (1) ... so that we have a linear DE?... Kind regards $\displaystyle \chi$ $\displaystyle \sigma$
No , the equation is 1 divided by the whole things, dy/dx =1/[2x+(e^(4y)]
Originally Posted by ryan1573 No , the equation is 1 divided by the whole things, dy/dx =1/[2x+(e^(4y)] dy =dx/[2x+(e^(4y)] [2x+(e^(4y)]dy=dx [2x+(e^(4y)]=dx/dy
Originally Posted by ryan1573 No , the equation is 1 divided by the whole things, dy/dx =1/[2x+(e^(4y)] Yes, it is. And that is equivalent to dx/dy= 2x+ e^(4y), as chisigma suggested! You have now had three people suggest the same way to solv this problem- try it!
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