1. ## Solve y'=1/[2x+(e^(4y)]

I need help to solve this equation, anyone could help me out?
y'=1/[2x+(e^(4y)] solve for y.

2. ## Re: Solve y'=1/[2x+(e^(4y)]

Originally Posted by ryan1573
I need help to solve this equation, anyone could help me out?
y'=1/[2x+(e^(4y)] solve for y.
Why don't write the DE as...

$\frac{d x}{d y} = 2 x + e^{4 y}$ (1)

... so that we have a linear DE?...

Kind regards

$\chi$ $\sigma$

3. ## Re: Solve y'=1/[2x+(e^(4y)]

No , the equation is 1 divided by the whole things, dy/dx =1/[2x+(e^(4y)]

4. ## Re: Solve y'=1/[2x+(e^(4y)]

Originally Posted by ryan1573
No , the equation is 1 divided by the whole things, dy/dx =1/[2x+(e^(4y)]

dy =dx/[2x+(e^(4y)]

[2x+(e^(4y)]dy=dx

[2x+(e^(4y)]=dx/dy

5. ## Re: Solve y'=1/[2x+(e^(4y)]

Originally Posted by ryan1573
No , the equation is 1 divided by the whole things, dy/dx =1/[2x+(e^(4y)]
Yes, it is. And that is equivalent to dx/dy= 2x+ e^(4y), as chisigma suggested!

You have now had three people suggest the same way to solv this problem- try it!