1. At high temperatures, nitrogen dioxide, NO2, decomposes into NO and O2. If y(t) is the concentration of NO2 (in moles per liter), then at 600ºK, y(t) changes according to the reaction law dy/dt = −.05y2 for time t in seconds.
A. Express y in terms of t and the initial concentration yo.
Equation of y in terms of t and initial concentration yo
Solve for constant of integration.
Solve for differential equation.
Hello, I can't seem to find the proper method to set up this problem. The chem. stuff is slightly misleading and I can't seem to come up with anything satisfying. Any help on setting this up would be appreciated!
The one below is merely an extension of the aforementioned question, when I figure out the one above it shouldn't be too difficult.
B. Assuming that the concentration of NO2 is twice as high at t = 20 seconds as it is at 100 seconds, find the exact initial concentration of the NO2. Reminder: “Exact” means no calculator numbers.
Exact initial concentration yo