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Math Help - First-Order Separable Equation

  1. #1
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    First-Order Separable Equation

    \frac{dy}{dx }=\frac{2}{27 }(x-3) \sqrt{\frac{x^2-6x+23}{y } }

    From an earlier part of the question I know that I need to use f(x)=(x^2 -6x+23)^\frac{3}{2 } f'(x)=\frac{3}{2 }(x^2 -6x+23)^\frac{1}{2 } (2x-6)

    I need a general solution in implicit form and then with y=2 and x=1 an explicit solution
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  2. #2
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    \displaystyle \begin{align*} \frac{dy}{dx} &= \frac{2}{27}(x - 3)\sqrt{\frac{x^2 - 6x + 23}{y}} \\ \frac{dy}{dx} &= \frac{2(x - 3)\sqrt{x^2 - 6x + 23}}{27\sqrt{y}} \\ \sqrt{y}\,\frac{dy}{dx} &= \frac{2(x - 3)\sqrt{x^2 - 6x + 23}}{27} \end{align*}

    You can now integrate both sides with respect to \displaystyle x.
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