Showing there is a limit cycle

Planar system:

x' = x-y-x^3

y'=x+y-y^3

only has a critical point at origin.

The question asks to show that this system has a periodic orbit.

The hint for this says to convert to polar coordinates and show that for all $\displaystyle \epsilon$>0, r'<0 on the circle r=sqrt(2)+$\displaystyle \epsilon$ and r'>0 on the circle r=1-$\displaystyle \epsilon$. Then show that this implies that there is a limit cycle in the annulus: {x$\displaystyle \in$R^2 : 1<= |x| <= sqrt(2)}.

I'm not sure how to even convert this to polar coordinates. I know that x=rcos($\displaystyle \theta$) and y=rsin($\displaystyle \theta$). But after i plug it in, I just get a equation and I don't know how to get r' or $\displaystyle \theta$' from it.