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Thread: 2nd order PDE

  1. May 22nd 2011, 01:06 PM #1
    morganfor
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    2nd order PDE

    How does one solve the PDE

    u_xx + u = 6y

    where u=u(x,y)

    thank you!
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  2. May 22nd 2011, 01:15 PM #2
    Danny
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    If you let u = 6y + v, then you get

    v_{xx} + v = 0

    This is an ODE but remember the constants of integration will depend on y.
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