Thread: Upward vertical movement with air drag.

\hat{} Hi, here's the problem: "upward vertical movement with air drag"
speed = v; initial speed at t0 = v0; initial height x0 = 0
x= vertical distance travelled

force gravity Fg=-m.g
force drag Fd=-k.v^2 (k=ct describing air, shape of object,...)

F=m.a :
--> m.a=-m.g-k.v^2 (a=x'' and y=x' and devide by mass m)
--> x'' = -g - (k/m).x'^2
--> x'' + (k/m).x'^2 = -g
--> what is the function of x in time, and of v in time?
That's a DE with second order and second degree, never learned this but am eager to learn it, searched som sites about DE but didn't easily find a way to solve this...
thanks for the help!
Bart

Originally Posted by bartroels

\hat{} Hi, here's the problem: "upward vertical movement with air drag"
speed = v; initial speed at t0 = v0; initial height x0 = 0
x= vertical distance travelled

force gravity Fg=-m.g
force drag Fd=-k.v^2 (k=ct describing air, shape of object,...)

F=m.a :
--> m.a=-m.g-k.v^2 (a=x'' and y=x' and devide by mass m)
--> x'' = -g - (k/m).x'^2
--> x'' + (k/m).x'^2 = -g
--> what is the function of x in time, and of v in time?
That's a DE with second order and second degree, never learned this but am eager to learn it, searched som sites about DE but didn't easily find a way to solve this...
thanks for the help!
Bart

Hint:

It may be easier to solve this problem in two parts

Let the acceleration be



Now you can write this as a first order ode



This equation is first order and separable!

Then use



to finish!