Your value for lambda is correct. But can you please tell me what you mean by k1 and k2? Are they values of the eigenvector?
ok so my problem is...
ok so when i started the problem i found that lambda was 0.
well i found that lambda squared was 0? so do i pick any value for k1 and k2? im not real sure of where to go from here?
any help would be appreciated...
thanks in advance.
So the characteristic polynomial is
So you have a repeated eigenvalue
This gives the one eigenvector
Now we need to find a generalized eigenvector
Reducing this gives
So we can pick
and we get the vector
So then the general solution is