Hi, can anyone show me how this is done: x' = rx - rx^2 Thanks, Ted C.
Follow Math Help Forum on Facebook and Google+
Originally Posted by tedchou12 Hi, can anyone show me how this is done: x' = rx - rx^2 Thanks, Ted C. If "r" is a constant then this is of variables seperable type CB
yes, r is a constant, separable variable? intergrate both sides?
Originally Posted by CaptainBlack If "r" is a constant then this is of variables seperable type CB Just as an aside (since CB's method is undoubtedly the easiest): it's also a Bernoulli equation.
Originally Posted by tedchou12 Hi, can anyone show me how this is done: x' = rx - rx^2 Thanks, Ted C. Yes, Integrate both sides.
View Tag Cloud