Hi, can anyone show me how this is done: x' = rx - rx^2 Thanks, Ted C.
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Originally Posted by tedchou12 Hi, can anyone show me how this is done: x' = rx - rx^2 Thanks, Ted C. If "r" is a constant then this is of variables seperable type CB
yes, r is a constant, separable variable? intergrate both sides?
Originally Posted by CaptainBlack If "r" is a constant then this is of variables seperable type CB Just as an aside (since CB's method is undoubtedly the easiest): it's also a Bernoulli equation.
Originally Posted by tedchou12 Hi, can anyone show me how this is done: x' = rx - rx^2 Thanks, Ted C. Yes, $\displaystyle \frac{dx}{x- x^2}= r dt$ Integrate both sides.
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