Hi, can anyone show me how this is done:

x' = rx - rx^2

Thanks,

Ted C.

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- May 3rd 2011, 02:12 AMtedchou12non linear 1st order
Hi, can anyone show me how this is done:

x' = rx - rx^2

Thanks,

Ted C. - May 3rd 2011, 03:07 AMCaptainBlack
- May 3rd 2011, 03:14 AMtedchou12
yes, r is a constant, separable variable? intergrate both sides?

- May 3rd 2011, 03:15 AMAckbeet
Just as an aside (since CB's method is undoubtedly the easiest): it's also a Bernoulli equation.

- May 3rd 2011, 09:55 AMHallsofIvy