Hi, can anyone show me how this is done:

x' = rx - rx^2

Thanks,

Ted C.

Printable View

- May 3rd 2011, 01:12 AMtedchou12non linear 1st order
Hi, can anyone show me how this is done:

x' = rx - rx^2

Thanks,

Ted C. - May 3rd 2011, 02:07 AMCaptainBlack
- May 3rd 2011, 02:14 AMtedchou12
yes, r is a constant, separable variable? intergrate both sides?

- May 3rd 2011, 02:15 AMAckbeet
Just as an aside (since CB's method is undoubtedly the easiest): it's also a Bernoulli equation.

- May 3rd 2011, 08:55 AMHallsofIvy