How can I solve this equation using the method of variation of parameters?Using the auxiliary equation the roots are and .
I don't know if I'm suppose to look for a solution of the form manly because the initial equation has o 1+... after the equal sign .Can someone please help me?
m1=1 and m2=-1....I don't know why I had the impression that the equation is x''-x'=... and not x''-x=...
I know that this method is called variation of parameters manly because we have varied the usual parameters
,A and B for instance, and made them functions x(t)=u1(t)x1(t)+u2(t)x2(t)