Results 1 to 2 of 2

Math Help - Solve dz/dx-z(2yx+x^2)=x pls help.

  1. #1
    Newbie
    Joined
    Apr 2011
    Posts
    2

    Solve dz/dx-z(2yx+x^2)=x pls help.

    Solve dz/dx-z(2yx+x^2)=x where y =1

    i.e dz/dx=2zx+zx^2+x

    pls also illustrate the procedure
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Forum Admin topsquark's Avatar
    Joined
    Jan 2006
    From
    Wellsville, NY
    Posts
    9,845
    Thanks
    320
    Awards
    1
    Quote Originally Posted by snehalkhair View Post
    Solve dz/dx-z(2yx+x^2)=x where y =1

    i.e dz/dx=2zx+zx^2+x

    pls also illustrate the procedure
    This is a first order linear ODE. (At least for y = 1.)

    dz/dx - (2x + x^2)z = x

    If you can't think of any other way, you can always find an integrating factor. The equation is in the form
    z' + P(x)z = Q(x)

    so the integrating factor will be of the form:
    exp[ (integral) P(x) dx ]

    -Dan

    Edit: This leaves one heck of an integral to try and solve, though. You might do better to do a series solution...
    Last edited by topsquark; April 17th 2011 at 10:29 AM.
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. need to solve summation equation to solve sum(x2)
    Posted in the Statistics Forum
    Replies: 2
    Last Post: July 16th 2010, 10:29 PM
  2. Replies: 1
    Last Post: June 9th 2009, 10:37 PM
  3. how do I solve this?
    Posted in the Calculus Forum
    Replies: 5
    Last Post: January 22nd 2009, 06:21 PM
  4. How could i solve?
    Posted in the Algebra Forum
    Replies: 2
    Last Post: January 2nd 2009, 02:18 PM
  5. Solve for x
    Posted in the Trigonometry Forum
    Replies: 3
    Last Post: January 1st 2009, 12:33 PM

Search Tags


/mathhelpforum @mathhelpforum