Thread: Question regarding a system of DE's and eigenvalues.

Dear Colleagues,

Could you please help me in solving the following problem:
Show that if is not an eigenvalue of an constant matrix , then is a solution of
- ,
where and are constant vectors.


Best Regards,

Raed.

Substitute x =k e^{ wt } in the equation. You'll obtain wk = Ak - b .

If w is not an eigenvalue of A then, you can choose k = (A-w I )^{ -1 } b .