# Math Help - Hard Time Applying a Boundary Condition

1. ## Hard Time Applying a Boundary Condition

So the solution to an ODE derived in Heat and Mass Transfer is
$ln(1-x)=c_1z+c_2$ where x=fn(z)

where,
$@z=z_1, x=x_1$ and
$@z=z_2, x=x_2$

Our professor gave us the answer with the applied boundary conditions as follows:
$((1-x)/(1-x_1))=((1-x_2)/(1-x_1))^n$
where
$n=(z-z_1)/(z_2-z_1)$

which i do not know how to derive at the end!!!

He also gave us a trick which involves manipulating the c1 and c2 constants, as follows:

Let $c_1=ln(k_1)$ & $c_2=ln(k_2)$

Thus
$ln(1-x)=c_1z+c_2$ becomes
$ln(1-x)=ln(k_1)z+ln(k_2)$

Good luck for whoever tries to solve this, I will indeed give you the title of "The Beast" in this forum...I am counting on you guys, i need to know the procedure to solve this on my final

2. Originally Posted by ramzouzy
So the solution to an ODE derived in Heat and Mass Transfer is
$ln(1-x)=c_1z+c_2$ where x=fn(z)

where,
$@z=z_1, x=x_1$ and
$@z=z_2, x=x_2$

Our professor gave us the answer with the applied boundary conditions as follows:
$((1-x)/(1-x_1))=((1-x_2)/(1-x_1))^n$
where
$n=(z-z_1)/(z_2-z_1)$

which i do not know how to derive at the end!!!

He also gave us a trick which involves manipulating the c1 and c2 constants, as follows:

Let $c_1=ln(k_1)$ & $c_2=ln(k_2)$

Thus
$ln(1-x)=c_1z+c_2$ becomes
$ln(1-x)=ln(k_1)z+ln(k_2)$

Good luck for whoever tries to solve this, I will indeed give you the title of "The Beast" in this forum...I am counting on you guys, i need to know the procedure to solve this on my final
In response to the part in red, is this a question from your final exam or is this a question from a review sheet? It's against MHF policy to knowingly help someone with an assignment/exam that counts toward your final grade. Please PM me to discuss this further.

Until then, this thread will remain closed.

EDIT: Thread reopened after correspondence with user; it was a question that was done in class, but the professor left out details.