# Thread: Inverse of Laplace Transform

1. ## Inverse of Laplace Transform

Iam trying to find the inverse of the attached laplace transform,
Dont know how to rearrange the 1st part to get it into a standard form to apply the inverse?

I've tried using partial Fraction but I have the exponential term I dont know what to do with?
The correct ans is on the bottom of the page.

2. Hint: $\displaystyle \displaystyle \mathcal{L}^{-1}\left[e^{-as}F(s)\right] = f(t-a)H(t-a)$.

3. thanks prove it ,i'll give it another go

4. I can see that e^(-2t) = H(t-2)

but cant see how to get F(s) out of 1/(s^3 + s)

L{f(t)} = F(s)

5. Originally Posted by heatly
but cant see how to get F(s) out of 1/(s^3 + s)
Hint: What is the Laplace transform of 1 - cos(kt)?

-Dan

6. Originally Posted by heatly
I can see that e^(-2t) = H(t-2)

but cant see how to get F(s) out of 1/(s^3 + s)

L{f(t)} = F(s)
Factorise the denominator and use Partial Fractions.

7. Thanks a heap prove it and topsquark.

I finally got it.