Can anybody see where Iam going wrong in the attached working?

The ans is:

Laplace Transform (sin2t) =

2/(s^2 + 4)

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- Apr 8th 2011, 06:34 PMheatlyLaplace Transformations
Can anybody see where Iam going wrong in the attached working?

The ans is:

Laplace Transform (sin2t) =

2/(s^2 + 4) - Apr 8th 2011, 07:20 PMtopsquark
$\displaystyle \displaystyle u = e^{-st} \implies du = -s \cdot e^{-st}dt$, not $\displaystyle \displaystyle du = -\frac{1}{s}e^{-st}dt$.

-Dan - Apr 8th 2011, 08:37 PMheatly
Thanks Dan

Much appreciated!