\int is

You should write your rearrangement as

and then integrate. I'm not sure I buy your integration. Try again.

Results 1 to 7 of 7

- Apr 6th 2011, 08:16 AM #1

- Apr 6th 2011, 08:19 AM #2

- Apr 6th 2011, 08:46 AM #3

- Apr 6th 2011, 08:50 AM #4

- Apr 6th 2011, 09:14 AM #5

- Joined
- Apr 2005
- Posts
- 18,201
- Thanks
- 2427

Why the questions marks? You had before

(except that you had "y" instead of "dy")

Now integrate both sides: the integral of a constant is that constant times x and the integral of x is

but cannot see where this 2nd part comes from.

My answer

Perhaps you misread the as .

is different from the solution in the book. The solution in the book is

can you show me where im goin wrong please. many thanks

- Apr 6th 2011, 09:20 AM #6

- Apr 6th 2011, 11:15 AM #7