The problem is +2x = 3

by re-arranging I get the following

y= dx

but need help with finding the general solution

i integrated an came up with.

y = +C

p.s. what is the source code for integral sign?

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- Apr 6th 2011, 08:16 AMdecoy8085dy/dx + 2x = 3.
The problem is +2x = 3

by re-arranging I get the following

y= dx

but need help with finding the general solution

i integrated an came up with.

y = +C

p.s. what is the source code for integral sign? - Apr 6th 2011, 08:19 AMAckbeet
\int is

You should write your rearrangement as

and then integrate. I'm not sure I buy your integration. Try again. - Apr 6th 2011, 08:46 AMdecoy808
okey i have tried again...

,

but cannot see where this 2nd part comes from.

My answer

is different from the solution in the book. The solution in the book is

can you show me where im goin wrong please. many thanks :) - Apr 6th 2011, 08:50 AMAckbeet
Where did the 7 come from?

- Apr 6th 2011, 09:14 AMHallsofIvy
Why the questions marks? You had before

(except that you had "y" instead of "dy")

Now integrate both sides: the integral of a constant is that constant times x and the integral of x is

Quote:

but cannot see where this 2nd part comes from.

My answer

Perhaps you misread the as .

Quote:

is different from the solution in the book. The solution in the book is

can you show me where im goin wrong please. many thanks :)

- Apr 6th 2011, 09:20 AMdecoy808
need to go back over integration. thanks guys

- Apr 6th 2011, 11:15 AMAckbeet
You're welcome for my contribution.