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Math Help - Laplacian Inverse Calculation

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    Laplacian Inverse Calculation

    So I'm to find \mathcal{L}^{-1}\{e^{-\pi}}/(s^{2}+1)\} and I figure it should just be: The exponential tells me its unit step-functioned over by \pi and then just Laplacian inverse the leftover so the result is \sin(t-\pi) \mathcal{U}(t-\pi). My book says it's -\sin t \mathcal{U}(t-\pi) and I don't get it.
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    Forum Admin topsquark's Avatar
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    Quote Originally Posted by ragnar View Post
    So I'm to find \mathcal{L}^{-1}\{e^{-\pi}}/(s^{2}+1)\} and I figure it should just be: The exponential tells me its unit step-functioned over by \pi and then just Laplacian inverse the leftover so the result is \sin(t-\pi) \mathcal{U}(t-\pi). My book says it's -\sin t \mathcal{U}(t-\pi) and I don't get it.
    Isn't sin(t - Pi) = -sin(t)?

    -Dan
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    Yep, just didn't see it because I'm retarded. Thanks.
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    Forum Admin topsquark's Avatar
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    Quote Originally Posted by ragnar View Post
    Yep, just didn't see it because I'm retarded. Thanks.
    Don't beat yourself up. We've all been there.

    -Dan
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