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Math Help - dC/dt=(1/tau)(Cin - C )

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    dC/dt=(1/tau)(Cin - C )

    The differential equa below and its solution.

    Can somebody please show me how thiss solution to the DE has been made?


    dC/dt=(1/tau)(Cin - C )

    C= Cin (1-e^(-t/Tau) )
    Last edited by mr fantastic; April 3rd 2011 at 04:26 AM. Reason: Re-titled.
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    First of all, please make sure you use capitals and lowercase letters consistently... Is c the same as C? And is Cin a constant?
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    Sorry bout that,
    I have fixed that now.

    Yes Cin is a constant.
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    Quote Originally Posted by heatly View Post
    The differential equa below and its solution.

    Can somebody please show me how thiss solution to the DE has been made?


    dC/dt=(1/tau)(Cin - C )

    C= Cin (1-e^(-t/Tau) )
    Step 1: \displaystyle \frac{dt}{dC} = \frac{\tau}{C_{in} - C}.

    Remaining steps are yours. If you need more help, please show all your work and say where you get stuck.
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