The differential equa below and its solution.

Can somebody please show me how thiss solution to the DE has been made?

dC/dt=(1/tau)(Cin - C )

C= Cin (1-e^(-t/Tau) )

Results 1 to 4 of 4

- April 3rd 2011, 01:47 AM #1

- Joined
- Apr 2009
- Posts
- 90

## dC/dt=(1/tau)(Cin - C )

The differential equa below and its solution.

Can somebody please show me how thiss solution to the DE has been made?

dC/dt=(1/tau)(Cin - C )

C= Cin (1-e^(-t/Tau) )

- April 3rd 2011, 01:58 AM #2

- April 3rd 2011, 04:18 AM #3

- Joined
- Apr 2009
- Posts
- 90

- April 3rd 2011, 04:27 AM #4