The differential equa below and its solution.

Can somebody please show me how thiss solution to the DE has been made?

dC/dt=(1/tau)(Cin - C )

C= Cin (1-e^(-t/Tau) )

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- April 3rd 2011, 12:47 AM #1

- Joined
- Apr 2009
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## dC/dt=(1/tau)(Cin - C )

The differential equa below and its solution.

Can somebody please show me how thiss solution to the DE has been made?

dC/dt=(1/tau)(Cin - C )

C= Cin (1-e^(-t/Tau) )

- April 3rd 2011, 12:58 AM #2

- April 3rd 2011, 03:18 AM #3

- Joined
- Apr 2009
- Posts
- 87

- April 3rd 2011, 03:27 AM #4