Originally Posted by

**Wolvenmoon** http://www.wolframalpha.com/input/?i=dy%2Fdx%3Dx^2*%28y^%281%2F2%29%29%2Cy%280%29%3D 1&asynchronous=false&equal=Submit

Alright, so I have wolfram alpha out and am trying to figure this problem out. It's one I missed on my review.

The problem: dy/dx=x^2*y^(1/2)

My answer y=x^6/36+c^2, C=1

My review sheet's answer: 2*y*(1/2) = 1/3 * x^3 + 2.

I'm in the center of it quite confused and would like to see the problem worked step by step to the review sheet answer, and beyond if any of you are feeling really nice. Thanks!