$\displaystyle y^{\prime\prime} - 5 y^{\prime} + 0 y=0$

To find the general solution, I just write the auxiliary expression:

$\displaystyle R^2-5R=0$

The solutions for R is 5,0

Therefore, my general solution should be:

$\displaystyle

Y=Ae^{5x}+B

$

But y''-5y'+0y=0 - Wolfram|Alpha

says otherwise. What am i missing here?