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Math Help - Simple DE problem

  1. #1
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    Simple DE problem

    y^{\prime\prime} - 5 y^{\prime} + 0 y=0

    To find the general solution, I just write the auxiliary expression:
    R^2-5R=0
    The solutions for R is 5,0

    Therefore, my general solution should be:
    <br />
Y=Ae^{5x}+B<br />

    But y&#39;&#39;-5y&#39;&#43;0y&#61;0 - Wolfram|Alpha

    says otherwise. What am i missing here?
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  2. #2
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    Quote Originally Posted by Vamz View Post
    What am i missing here?

    Nothing, your solution is fine, just find y' and y'' from your solution and check it in the equation.

    Wolfram's solution is also fine.

    They are actually the same if you make \displaystyle A = \frac{1}{5}c_1
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