Originally Posted by
LHS So by expressing cos^2(theta) as 1/2+1/2 cos(2*theta) I can equate with the general solution to laplace in polars? which is
T(x,y)=A[0]+B[0]log(r)+ (the infinite summation from n=1 of) (A[n]r^n+B[n]r^-n)(C[n]cos(n theta)+D[n]sin(n theta))?