Suppose that an object weighing 4lbs stretches a spring 2 inches. The object is displaced an additional six inches below the equilibrium position and then released. The object is in a medium that exerts a damping force nemuerically equal to 2 times the instantaneous velocity. Determine the equation of motion.
So, Here I know that since F=ks by Hooke's Law, we can determine k as follows:
Now, since from newton's second law we know that , where and and we can equate this to the sum of the restoring force of the spring and the resistant force of the medium so that
Am I on the right track?