Are the x's meant to be y's ....? Are there boundary conditions? Note that by inspection sin(y) = y/2 for y = 0 but the other solutions cannot be found in closed form using algebra: solve Sin[x] = x/2 - Wolfram|Alpha
Are the x's meant to be y's ....? Are there boundary conditions? Note that by inspection sin(y) = y/2 for y = 0 but the other solutions cannot be found in closed form using algebra: solve Sin[x] = x/2 - Wolfram|Alpha