If you let then the DE becomes
.
The integrating factor is . Multiplying both sides of the DE by the integrating factor gives
.
ok so the problem is
xy'' - 4y' = x^4
im getting a different answer from the book and was wondering if someone could check my work.
Yc= c1 + c2x^5
W = 5x^4
W1 = -x^9
W2 = x^4
it seems that the book is using f(x) = x^3???
i thought the f(x) function would be x^4?
thanks in advance....