Hey all,

Given the differential equation:

$\displaystyle \frac{dy}{dt}=\frac{1}{2y+1}$, where $\displaystyle x$ is not $\displaystyle -\frac{1}{2}$

I do not understand how they went from:

$\displaystyle \int(2y+1)dy = \int tdt$

$\displaystyle y^2+y = t + k$

to

$\displaystyle y(t) = \frac{-1\pm \sqrt{4t+4k+1}}{2}$