y'' -3y + 2y = e^2ix
Will this imaginary constant make some trouble for me?
I have tried this
Y = Ae2ix
and the derivative of that
Y' = 2Ae^2ix
Y''= 4Ae^2ix
I cant figure out how to get the full solution, because I already have the homogenous equation solved. what about this, what will be the constants?